Tricky Train Journey
A train leaves London at 9:00 a.m. and travels at an average speed of 60 km/h. Another train leaves the same station at 9:30 a.m. and travels at an average speed of 80 km/h, following the same route.
At what time will the faster train catch up with the slower one?
Step 1: How far has the first train travelled by 9:30 a.m.?
ReplyDeleteTime difference = 30 minutes = 0.5 hours
Distance = Speed × Time = 60 km/h × 0.5 h = 30 km
So, the first train has a 30 km head start when the second train leaves at 9:30 a.m.
Step 2: Relative speed
The second train is faster:
80 km/h – 60 km/h = 20 km/h (this is how quickly it is closing the gap)
Step 3: Time to catch up
Time = Distance ÷ Speed = 30 km ÷ 20 km/h = 1.5 hours
Step 4: Add to 9:30 a.m.
9:30 a.m. + 1.5 hours = 11:00 a.m.