Free Online 11+ Maths Tutoring – Open to All

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Free Online 11+ Maths Tutoring – Open to All Hi! I’m Rithvik Muthuvelu , a GCSE student at King Edward’s School, Birmingham , and I’m offering free weekly online maths sessions to help students prepare for the 11+ entrance exams . These sessions are open to anyone who wants to improve their maths skills—no school restrictions. What You’ll Get Free weekly online maths classes Focused 11+ preparation : problem-solving, arithmetic, word problems, exam strategies Small-group format for better interaction Ideal for Year 4 and Year 5 students How to Join Weekly Session: Saturdays at 2:00 PM Google Meet Link: https://meet.google.com/nrk-iwmh-gij Contact Email: rithvikmu1@gmail.com If your child is preparing for the 11+ and would like extra support, feel free to join the class or get in touch. Looking forward to helping more students learn and grow! — Rithvik Muthuvelu  
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Tricky Train Journey

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A train leaves London at 9:00 a.m. and travels at an average speed of 60 km/h. Another train leaves the same station at 9:30 a.m. and travels at an average speed of 80 km/h, following the same route.

At what time will the faster train catch up with the slower one?

Comments

  1. Rithvik24 September 2025 at 17:26

    Step 1: How far has the first train travelled by 9:30 a.m.?

    Time difference = 30 minutes = 0.5 hours

    Distance = Speed × Time = 60 km/h × 0.5 h = 30 km

    So, the first train has a 30 km head start when the second train leaves at 9:30 a.m.

    Step 2: Relative speed

    The second train is faster:
    80 km/h – 60 km/h = 20 km/h (this is how quickly it is closing the gap)

    Step 3: Time to catch up

    Time = Distance ÷ Speed = 30 km ÷ 20 km/h = 1.5 hours

    Step 4: Add to 9:30 a.m.

    9:30 a.m. + 1.5 hours = 11:00 a.m.

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