How many apples

A farmer packed some apples into bags. He filled 1/3 of the bags with 6 apples each, 1/2 of the bags with 4 apples each, and the remaining 4 bags with 10 apples each.

If he used a total of 36 bags, how many apples did he pack altogether?

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  1. Step 1: Find out how many bags are in each group.

    Total bags = 36

    1/3 of 36 = 12 bags (with 6 apples each)

    1/2 of 36 = 18 bags (with 4 apples each)
    So far: 12 + 18 = 30 bags used

    Remaining bags = 36 - 30 = 6 bags, but the question says 4 bags are left.
    → This shows a contradiction, so let’s check carefully.

    Problem says:

    1/3 of the bags → 6 apples each

    1/2 of the bags → 4 apples each

    Remaining 4 bags → 10 apples each

    Let’s call the total number of bags = x

    Then:

    Bags with 6 apples = (1/3)x

    Bags with 4 apples = (1/2)x

    Bags with 10 apples = 4

    So:

    (1/3)x + (1/2)x + 4 = x

    Step 2: Solve for x

    Find a common denominator (LCD of 3 and 2 is 6):

    (1/3)x = 2x/6
    (1/2)x = 3x/6

    So:

    2x/6 + 3x/6 + 4 = x
    (5x/6) + 4 = x

    Now subtract 5x/6 from both sides:

    4 = x - 5x/6
    4 = x(1 - 5/6)
    4 = x(1/6)

    Multiply both sides by 6:

    x = 24

    Total bags = 24

    Now calculate how many bags in each group:

    1/3 of 24 = 8 bags with 6 apples

    1/2 of 24 = 12 bags with 4 apples

    Remaining = 24 - (8 + 12) = 4 bags with 10 apples ✅

    Step 3: Calculate total apples

    8 bags × 6 apples = 48 apples

    12 bags × 4 apples = 48 apples

    4 bags × 10 apples = 40 apples

    Total = 48 + 48 + 40 = 136 apples

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