Free Online 11+ Maths Tutoring – Open to All

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Free Online 11+ Maths Tutoring – Open to All Hi! I’m Rithvik Muthuvelu , a GCSE student at King Edward’s School, Birmingham , and I’m offering free weekly online maths sessions to help students prepare for the 11+ entrance exams . These sessions are open to anyone who wants to improve their maths skills—no school restrictions. What You’ll Get Free weekly online maths classes Focused 11+ preparation : problem-solving, arithmetic, word problems, exam strategies Small-group format for better interaction Ideal for Year 4 and Year 5 students How to Join Weekly Session: Saturdays at 2:00 PM Google Meet Link: https://meet.google.com/nrk-iwmh-gij Contact Email: rithvikmu1@gmail.com If your child is preparing for the 11+ and would like extra support, feel free to join the class or get in touch. Looking forward to helping more students learn and grow! — Rithvik Muthuvelu  
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What is the number?

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A number is increased by 3, then multiplied by 4. The result is the same as if the number had first been multiplied by 4 and then increased by 24.
What is the number?


Comments

  1. Rithvik10 August 2025 at 09:57

    Let the number be x.

    First method (increase, then multiply):
    Increase by 3 → x + 3
    Multiply by 4 → 4(x + 3)

    Second method (multiply, then increase):
    Multiply by 4 → 4x
    Increase by 24 → 4x + 24

    We are told these are equal:
    4(x + 3) = 4x + 24

    Expand the left-hand side:
    4x + 12 = 4x + 24

    Subtract 4x from both sides:
    12 = 24

    Uh-oh — this is not true.

    ReplyDelete
  2. Rithvik10 August 2025 at 09:58

    There is no number that satisfies this condition.
    This is one of those sneaky 11 Plus questions where the algebra shows the situation is impossible.

    ReplyDelete

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