Free Online 11+ Maths Tutoring – Open to All

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Free Online 11+ Maths Tutoring – Open to All Hi! I’m Rithvik Muthuvelu , a GCSE student at King Edward’s School, Birmingham , and I’m offering free weekly online maths sessions to help students prepare for the 11+ entrance exams . These sessions are open to anyone who wants to improve their maths skills—no school restrictions. What You’ll Get Free weekly online maths classes Focused 11+ preparation : problem-solving, arithmetic, word problems, exam strategies Small-group format for better interaction Ideal for Year 4 and Year 5 students How to Join Weekly Session: Saturdays at 2:00 PM Google Meet Link: https://meet.google.com/nrk-iwmh-gij Contact Email: rithvikmu1@gmail.com If your child is preparing for the 11+ and would like extra support, feel free to join the class or get in touch. Looking forward to helping more students learn and grow! — Rithvik Muthuvelu  
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Train Travel: Time and Distance Problem

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A train travels from Station A to Station B, a distance of 180 kilometres, at a constant speed. If the train increases its speed by 15 kilometres per hour, it would take 1 hour less to cover the same distance.

What is the original speed of the train?

Comments

  1. Rithvik4 September 2024 at 05:40

    Let the original speed of the train be x kilometers per hour.

    Time taken at the original speed:

    Time = 180 / x

    Time taken at the increased speed:

    Increased speed = x + 15

    Time = 180 / (x + 15)

    According to the problem:

    180 / x - 180 / (x + 15) = 1

    Solving the equation:

    (180(x + 15) - 180x) / (x(x + 15)) = 1

    2700 / (x(x + 15)) = 1

    x(x + 15) = 2700

    x^2 + 15x - 2700 = 0

    Factoring the quadratic equation:

    (x - 45)(x + 60) = 0

    Finding the positive value for speed:

    x = 45 (since speed cannot be negative)

    Original Speed of the Train: 45 kilometers per hour.

    ReplyDelete

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