Free Online 11+ Maths Tutoring – Open to All
Free Online 11+ Maths Tutoring – Open to All Hi! I’m Rithvik Muthuvelu , a GCSE student at King Edward’s School, Birmingham , and I’m offering free weekly online maths sessions to help students prepare for the 11+ entrance exams . These sessions are open to anyone who wants to improve their maths skills—no school restrictions. What You’ll Get Free weekly online maths classes Focused 11+ preparation : problem-solving, arithmetic, word problems, exam strategies Small-group format for better interaction Ideal for Year 4 and Year 5 students How to Join Weekly Session: Saturdays at 2:00 PM Google Meet Link: https://meet.google.com/nrk-iwmh-gij Contact Email: rithvikmu1@gmail.com If your child is preparing for the 11+ and would like extra support, feel free to join the class or get in touch. Looking forward to helping more students learn and grow! — Rithvik Muthuvelu
The total number of items (balloons + hats) is 20. This can be written as:
ReplyDeleteB+H=20
The total cost is $18.40, with balloons costing $0.50 each and hats costing $1.20 each. This can be written as:
0.50B+1.20H=18.40
B+H=20 (Equation 1)
0.50B+1.20H=18.40 (Equation 2)
We can use either the substitution method or the elimination method. For this problem, either method works, but let's use the elimination method as an example.
you can multiply the first equation by 0.50:
0.50B+0.50H=10 (Modified Equation 1)
Subtract One Equation from the Other:
Now, subtract the modified Equation 1 from Equation 2:
(0.50B+1.20H)−(0.50B+0.50H)=18.40−10
Simplifying this gives:
0.70H=8.40
H= 0.70/8.40 =12
Now, substitute
H=12 into one of the original equations (e.g., Equation 1) to find
B+12=20
B=20−12=8
So, the solution is
meaning Sophia bought 8 balloons and 12 party hats.