Free Online 11+ Maths Tutoring – Open to All

Free Online 11+ Maths Tutoring – Open to All Hi! I’m Rithvik Muthuvelu , a GCSE student at King Edward’s School, Birmingham , and I’m offering free weekly online maths sessions to help students prepare for the 11+ entrance exams . These sessions are open to anyone who wants to improve their maths skills—no school restrictions. What You’ll Get Free weekly online maths classes Focused 11+ preparation : problem-solving, arithmetic, word problems, exam strategies Small-group format for better interaction Ideal for Year 4 and Year 5 students How to Join Weekly Session: Saturdays at 2:00 PM Google Meet Link: https://meet.google.com/nrk-iwmh-gij Contact Email: rithvikmu1@gmail.com If your child is preparing for the 11+ and would like extra support, feel free to join the class or get in touch. Looking forward to helping more students learn and grow! — Rithvik Muthuvelu  

How long is the diagonal path

A rectangular garden is 15 meters long and 12 meters wide. The garden is divided into two equal sections by a diagonal path that runs from one corner to the opposite corner. What is the length of the diagonal path?

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  1. To find the length of the diagonal path that divides the rectangular garden into two equal sections, you can use the Pythagoras theorem. In a right triangle formed by the length, width, and diagonal, the diagonal is the hypotenuse, and the length and width are the legs of the triangle.

    Let's label the length as 'a' (15 meters), the width as 'b' (12 meters), and the diagonal as 'c'. According to the Pythagoras theorem:

    c^2 = a^2 + b^2

    Substitute the values:

    c^2 = 15^2 + 12^2
    c^2 = 225 + 144
    c^2 = 369

    Now, take the square root of both sides to solve for 'c':

    c = √369
    c ≈ 19.24 meters

    So, the length of the diagonal path is approximately 19.24 meters.

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