Free Online 11+ Maths Tutoring – Open to All
Free Online 11+ Maths Tutoring – Open to All Hi! I’m Rithvik Muthuvelu , a GCSE student at King Edward’s School, Birmingham , and I’m offering free weekly online maths sessions to help students prepare for the 11+ entrance exams . These sessions are open to anyone who wants to improve their maths skills—no school restrictions. What You’ll Get Free weekly online maths classes Focused 11+ preparation : problem-solving, arithmetic, word problems, exam strategies Small-group format for better interaction Ideal for Year 4 and Year 5 students How to Join Weekly Session: Saturdays at 2:00 PM Google Meet Link: https://meet.google.com/nrk-iwmh-gij Contact Email: rithvikmu1@gmail.com If your child is preparing for the 11+ and would like extra support, feel free to join the class or get in touch. Looking forward to helping more students learn and grow! — Rithvik Muthuvelu
Let's denote the ages of Alice, Bob, and Carol as A, B, and C respectively.
ReplyDeleteWe have three pieces of information:
Alice is twice as old as Bob: A = 2B
Carol is three years older than Bob: C = B + 3
The sum of their ages is 45 years: A + B + C = 45
Now we can substitute the expressions from the first two points into the third equation:
A + B + C = 45
(2B) + B + (B + 3) = 45
4B + 3 = 45
4B = 42
B = 10.5
Now that we know Bob's age, we can find Alice's age using the first equation:
A = 2B = 2 * 10.5 = 21
And we can find Carol's age using the second equation:
C = B + 3 = 10.5 + 3 = 13.5
So, the ages of Alice, Bob, and Carol are 21 years, 10.5 years, and 13.5 years respectively.