Free Online 11+ Maths Tutoring – Open to All

Free Online 11+ Maths Tutoring – Open to All Hi! I’m Rithvik Muthuvelu , a GCSE student at King Edward’s School, Birmingham , and I’m offering free weekly online maths sessions to help students prepare for the 11+ entrance exams . These sessions are open to anyone who wants to improve their maths skills—no school restrictions. What You’ll Get Free weekly online maths classes Focused 11+ preparation : problem-solving, arithmetic, word problems, exam strategies Small-group format for better interaction Ideal for Year 4 and Year 5 students How to Join Weekly Session: Saturdays at 2:00 PM Google Meet Link: https://meet.google.com/nrk-iwmh-gij Contact Email: rithvikmu1@gmail.com If your child is preparing for the 11+ and would like extra support, feel free to join the class or get in touch. Looking forward to helping more students learn and grow! — Rithvik Muthuvelu  

Alice, Bob and Carol

Three friends, Alice, Bob, and Carol, are comparing their ages. Alice is twice as old as Bob, and Carol is three years older than Bob. The sum of their ages is 45 years. How old is each person?

Take your time to set up equations based on the given information and solve for the ages of Alice, Bob, and Carol.

Comments

  1. Let's denote the ages of Alice, Bob, and Carol as A, B, and C respectively.

    We have three pieces of information:

    Alice is twice as old as Bob: A = 2B
    Carol is three years older than Bob: C = B + 3
    The sum of their ages is 45 years: A + B + C = 45
    Now we can substitute the expressions from the first two points into the third equation:

    A + B + C = 45
    (2B) + B + (B + 3) = 45
    4B + 3 = 45
    4B = 42
    B = 10.5

    Now that we know Bob's age, we can find Alice's age using the first equation:
    A = 2B = 2 * 10.5 = 21

    And we can find Carol's age using the second equation:
    C = B + 3 = 10.5 + 3 = 13.5

    So, the ages of Alice, Bob, and Carol are 21 years, 10.5 years, and 13.5 years respectively.

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