Free Online 11+ Maths Tutoring – Open to All

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Free Online 11+ Maths Tutoring – Open to All Hi! I’m Rithvik Muthuvelu , a GCSE student at King Edward’s School, Birmingham , and I’m offering free weekly online maths sessions to help students prepare for the 11+ entrance exams . These sessions are open to anyone who wants to improve their maths skills—no school restrictions. What You’ll Get Free weekly online maths classes Focused 11+ preparation : problem-solving, arithmetic, word problems, exam strategies Small-group format for better interaction Ideal for Year 4 and Year 5 students How to Join Weekly Session: Saturdays at 2:00 PM Google Meet Link: https://meet.google.com/nrk-iwmh-gij Contact Email: rithvikmu1@gmail.com If your child is preparing for the 11+ and would like extra support, feel free to join the class or get in touch. Looking forward to helping more students learn and grow! — Rithvik Muthuvelu  
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Algebra problems

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A bird has 2 legs, a cat has 4 legs, an insect has 6 legs and a spider has 8 legs. Claire looks at some animals and counts all their legs. She counts 38 legs. There are twice as many birds as spiders and twice as many cats as insects. How many of each type of animal can she see?

Comments

  1. Anonymous30 October 2020 at 17:43

    Well if b = the bird, c = the cat, i = the insect and s = the spider, B = 2S and C = 2i, we can make an equation.
    2(2S) + 8S + 4(2i) + 6i = 38
    12S + 14i = 38

    Now we now this, all we can do is just guess systematically.

    First let's see when there are no spiders:
    This will give us 14i = 38, which does not work.

    Secondly, let's see when there is 1 spider:
    This gives us 14i = 26, which again, won't work.

    Thirdly, let's see when there are 2 spiders:
    this gives us 14i = 14, which we can solve to get a whole number. It will give us i = 1. Now we can substitute the things we know into our first equation at figure out the solution. Try substituting for yourself!

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