Free Online 11+ Maths Tutoring – Open to All
Free Online 11+ Maths Tutoring – Open to All Hi! I’m Rithvik Muthuvelu , a GCSE student at King Edward’s School, Birmingham , and I’m offering free weekly online maths sessions to help students prepare for the 11+ entrance exams . These sessions are open to anyone who wants to improve their maths skills—no school restrictions. What You’ll Get Free weekly online maths classes Focused 11+ preparation : problem-solving, arithmetic, word problems, exam strategies Small-group format for better interaction Ideal for Year 4 and Year 5 students How to Join Weekly Session: Saturdays at 2:00 PM Google Meet Link: https://meet.google.com/nrk-iwmh-gij Contact Email: rithvikmu1@gmail.com If your child is preparing for the 11+ and would like extra support, feel free to join the class or get in touch. Looking forward to helping more students learn and grow! — Rithvik Muthuvelu
Let the tens digit be x, and the units digit be y.
ReplyDeleteThen:
The original number = 10x + y
The reversed number = 10y + x
From the question:
1) Reversed number is 27 more than the original:
10y + x = 10x + y + 27
2) Sum of digits is 11:
x + y = 11
Step 1: Rearranging the first equation
10y + x = 10x + y + 27
→ 10y − y + x − 10x = 27
→ 9y − 9x = 27
→ y − x = 3 ← (Equation A)
From before:
x + y = 11 ← (Equation B)
Step 2: Solve the equations
From Equation A:
y = x + 3
Substitute into Equation B:
x + (x + 3) = 11
→ 2x + 3 = 11
→ 2x = 8
→ x = 4
Now find y:
y = x + 3 = 4 + 3 = 7
Final Answer:
Original number = 10x + y = 10×4 + 7 = 47