Free Online 11+ Maths Tutoring – Open to All

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Free Online 11+ Maths Tutoring – Open to All Hi! I’m Rithvik Muthuvelu , a GCSE student at King Edward’s School, Birmingham , and I’m offering free weekly online maths sessions to help students prepare for the 11+ entrance exams . These sessions are open to anyone who wants to improve their maths skills—no school restrictions. What You’ll Get Free weekly online maths classes Focused 11+ preparation : problem-solving, arithmetic, word problems, exam strategies Small-group format for better interaction Ideal for Year 4 and Year 5 students How to Join Weekly Session: Saturdays at 2:00 PM Google Meet Link: https://meet.google.com/nrk-iwmh-gij Contact Email: rithvikmu1@gmail.com If your child is preparing for the 11+ and would like extra support, feel free to join the class or get in touch. Looking forward to helping more students learn and grow! — Rithvik Muthuvelu  
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The Chocolate Bar Challenge

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James and his friends are sharing a large chocolate bar. If James divides it equally among 4 friends, there are 3 pieces left. However, if he divides it equally among 7 friends, there is only 1 piece left. What is the smallest possible number of pieces in the chocolate bar?

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  1. Rithvik11 March 2025 at 07:36

    James has a chocolate bar with N pieces.

    When he divides it among 4 friends, there are 3 pieces left.
    When he divides it among 7 friends, there is 1 piece left.
    We need to find the smallest possible number of pieces in the chocolate bar.

    Step 1: Write the Conditions as Equations
    Since dividing by 4 leaves a remainder of 3, we can say:
    N = a multiple of 4 + 3 → (e.g., 3, 7, 11, 15, 19, 23, …)

    Since dividing by 7 leaves a remainder of 1, we can say:
    N = a multiple of 7 + 1 → (e.g., 1, 8, 15, 22, 29, 36, …)

    Step 2: Find the Smallest Common Number
    The smallest number that appears in both lists is 15.

    Final Answer:
    The chocolate bar has at least 15 pieces. ✅

    ReplyDelete

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