Free Online 11+ Maths Tutoring – Open to All
Free Online 11+ Maths Tutoring – Open to All Hi! I’m Rithvik Muthuvelu , a GCSE student at King Edward’s School, Birmingham , and I’m offering free weekly online maths sessions to help students prepare for the 11+ entrance exams . These sessions are open to anyone who wants to improve their maths skills—no school restrictions. What You’ll Get Free weekly online maths classes Focused 11+ preparation : problem-solving, arithmetic, word problems, exam strategies Small-group format for better interaction Ideal for Year 4 and Year 5 students How to Join Weekly Session: Saturdays at 2:00 PM Google Meet Link: https://meet.google.com/nrk-iwmh-gij Contact Email: rithvikmu1@gmail.com If your child is preparing for the 11+ and would like extra support, feel free to join the class or get in touch. Looking forward to helping more students learn and grow! — Rithvik Muthuvelu
Define Variables:
ReplyDeleteLet Maria's current age be M and her son's current age be S.
Translate the First Condition:
Five years ago, Maria was three times as old as her son.
M−5=3(S−5)
Translate the Second Condition:
In five years, she will be twice as old as her son.
M+5=2(S+5)
Set Up the Equations:
Now we have two equations:
M−5=3S−15
M+5=2S+10
Simplify the Equations:
Simplifying both equations:
M=3S−10
M=2S+5
Solve the Equations:
Since both expressions equal M, set them equal to each other and solve for S:
3S−10=2S+5
S=15 (Maria's son is 15 years old)
Find Maria's Age:
Substitute
S=15 into either equation to find M
M=3(15)−10=45−10=35 (Maria is 35 years old)
So, Maria is currently 35 years old, and her son is 15 years old.